Formula : .

Train Speed = Distance / Time.

Points to Remember .

To change km/hr into m/sec, we need to multiply it by 5 / 18. .

Example:.

90 km/hr means.

90 x 5 / 18.

= (5 x 5 ).

= 25 m/sec.

And if we need to convert m/sec into km/hr, we multiply it by 18 / 5.

Example:.

90 m/sec means.

90 x 18 / 5.

= ( 18 x 18 ).

= 324 km/hr.

Time taken by a train of length l meters to pass a pole or standing man or a signal post is equal to the time taken by the train to cover l meters.

Time taken by a train of length l meters to pass a stationary object of length b meters is the time taken by the train to cover (l + b) meters.

Suppose two trains or two objects bodies are mo Read full Tips & Tricks

Train Speed = Distance / Time.

Points to Remember .

To change km/hr into m/sec, we need to multiply it by 5 / 18. .

Example:.

90 km/hr means.

90 x 5 / 18.

= (5 x 5 ).

= 25 m/sec.

And if we need to convert m/sec into km/hr, we multiply it by 18 / 5.

Example:.

90 m/sec means.

90 x 18 / 5.

= ( 18 x 18 ).

= 324 km/hr.

Time taken by a train of length l meters to pass a pole or standing man or a signal post is equal to the time taken by the train to cover l meters.

Time taken by a train of length l meters to pass a stationary object of length b meters is the time taken by the train to cover (l + b) meters.

Suppose two trains or two objects bodies are mo Read full Tips & Tricks

Profit and loss is the one of major question section in Competitive exams. These formulas will be helpful for your upcoming Exams like PSC, SSC, IBPS and Other Competitive Exams. .

Cost Price(CP) : The Price at which a particular item purchased, is called its Cost Price.

Selling Price (SP): The price at which a particular item is sold, called its Selling Price.

Profit: If Selling Price of an item is more than Cost Price , then vendor is said to have a Profit.

Loss: if Selling Price of an item is less than Cost Price, the vendor said to have a Loss.

Formulas Profit = SP – CP.

Profit % = Profit/(CP)×100.

SP = ((100+Profit% )/100)×CP.

CP = (100/(100+Profit%))×SP.

Loss = CP – SP.

Loss% = Loss/(CP)×100.

SP = ((100-loss%)/100)×CP.

CP = (100/(100-loss%))×SP.

Read full Tips & Tricks

Cost Price(CP) : The Price at which a particular item purchased, is called its Cost Price.

Selling Price (SP): The price at which a particular item is sold, called its Selling Price.

Profit: If Selling Price of an item is more than Cost Price , then vendor is said to have a Profit.

Loss: if Selling Price of an item is less than Cost Price, the vendor said to have a Loss.

Formulas Profit = SP – CP.

Profit % = Profit/(CP)×100.

SP = ((100+Profit% )/100)×CP.

CP = (100/(100+Profit%))×SP.

Loss = CP – SP.

Loss% = Loss/(CP)×100.

SP = ((100-loss%)/100)×CP.

CP = (100/(100-loss%))×SP.

Read full Tips & Tricks

Shortcut tricks on boats and streams are one of the most important topics in exams. These are the formulas and examples on Boats and Streams (Cyclist and the wind or Swimmer and stream) questions. These examples will help you to better understand shortcut tricks on boats and streams questions.

There are multiple types of questions asked from these topics. The speed of the boat in still water and the speed of stream will give in questions, You have to find the time taken by boat to go upstream and downstream. .

The speed of the boat in up and down stream will give in question, you need to find the average speed of the boat.

The speed of boat to go up or down the stream will give in question, you need to find speed of boat in still water and speed of stream.

The time taken by boat to reach a place in up and downstream will given in question, you need to find the distance to the place.

LINE_F Read full Tips & Tricks

There are multiple types of questions asked from these topics. The speed of the boat in still water and the speed of stream will give in questions, You have to find the time taken by boat to go upstream and downstream. .

The speed of the boat in up and down stream will give in question, you need to find the average speed of the boat.

The speed of boat to go up or down the stream will give in question, you need to find speed of boat in still water and speed of stream.

The time taken by boat to reach a place in up and downstream will given in question, you need to find the distance to the place.

LINE_F Read full Tips & Tricks

Problems Type 1: .

A can finish work in X days. .

B can finish work in Y days.

Both can finish in Z days = (X*Y) / (X+Y). .

Problems Type 2: .

Both A and B together can do work in T days.

A can do this work in X days.

then, B can do it in Y days = (X*T) / (X-T) .

Problems Type 3: .

A can finish work in X days.

B can finish work in Y days.

C can finish work in Z days.

Together they can do work in T days = (X*Y*Z)/ [(X*Y)+(Y*Z)+(X*Z)] .

Problems Type 4: .

A can finish work in X days.

B can finish work in Y days.

A*X = B*Y.

Read full Tips & Tricks

A can finish work in X days. .

B can finish work in Y days.

Both can finish in Z days = (X*Y) / (X+Y). .

Problems Type 2: .

Both A and B together can do work in T days.

A can do this work in X days.

then, B can do it in Y days = (X*T) / (X-T) .

Problems Type 3: .

A can finish work in X days.

B can finish work in Y days.

C can finish work in Z days.

Together they can do work in T days = (X*Y*Z)/ [(X*Y)+(Y*Z)+(X*Z)] .

Problems Type 4: .

A can finish work in X days.

B can finish work in Y days.

A*X = B*Y.

Read full Tips & Tricks

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