Problems Type 1:
A can finish work in X days.
B can finish work in Y days.
Both can finish in Z days = (X*Y) / (X+Y).
Problems Type 2:
Both A and B together can do work in T days.
A can do this work in X days.
then, B can do it in Y days = (X*T) / (X-T)
Problems Type 3:
A can finish work in X days.
B can finish work in Y days.
C can finish work in Z days.
Together they can do work in T days = (X*Y*Z)/ [(X*Y)+(Y*Z)+(X*Z)]
Problems Type 4:
A can finish work in X days.
B can finish work in Y days.
A*X = B*Y
Y = (A*X) / B
Problems Type 5:
A can finish work in X days.
B can finish work in Y days.
A left work after P days then B need to work Q days
Q = [(X - P) / X ] * Y
Problems Type 6:
M1 person can do W1 work in D1 days and H1 hours
M2 person can do W2 work in D2 days and H2 hours
M1D1H1 = M2D2H2
Important Maths Formulas .
(a ± b) 2 = a 2 ± 2ab + b 2 .
(a + b + c) 2 = a 2 + b 2 + c 2 + 2(ab + bc + ca).
(a + b + c + d) 2 = a 2 + b 2 + c 2 + d 2 + 2(ab + ac + ad + bc + bd + cd) .
Geometry formulas .
Perimeter ( ചുറ്റളവ് ) .
Perimeter of a square: P=4a.
a: length of one side.
Perimeter of a rectangle: P=2(l+w).
l: length.
w: width.
Perimeter of a triangle: P=a+b+c.
a, b, and c: lengths of the 3 sides.
Area ( വിസ്തീര്ണ്ണം ) .
LINE_FE...
The quickest way to calculate percentages is to multiply numbers first and handle two decimal places later.
For example, 20% of 70 is 20 x 70 = 1400, so the answer is 14. .
70% of 20 is also 14.
To calculate the percentage of 72 or 29, then round up and down to the nearest multiple (70 and 30 respectively) to get a quick approx result.
...
Code -“BHAJI SABJI FOR MAASAAB”.
B : Babur.
H : Humayun.
A : Akbar.
JI : Jahangir.
S : Shah jahan.
A : Aurangazeb.
B : Bahadur shah.
JI : Jahandar shah.
For : Farrukhsiyar.
M : Muhammad Shah.
A : Ahmad Shah.
A : Alamgir II.
SA : Shah Alam II.
A : Akbar II.
B : Bahadur Shah Zafar.
...