(a ± b)2 = a2 ± 2ab + b2
(a + b + c)2 = a2 + b2 + c2 + 2(ab + bc + ca)
(a + b + c + d)2 = a2 + b2 + c2 + d2 + 2(ab + ac + ad + bc + bd + cd)
Perimeter ( ചുറ്റളവ് )
Perimeter of a square: P=4a
a: length of one side
Perimeter of a rectangle: P=2(l+w)
l: length
w: width
Perimeter of a triangle: P=a+b+c
a, b, and c: lengths of the 3 sides
Area of a square: A=a2
a: length of one side
Area of a rectangle: A=wl
l: length
w: width
Area of a triangle: A=(b × h)/2
b: length of the base
h: length of the height
Area of a trapezoid: A=(b1 + b2) × h/2
b1 and b2: parallel sides or the bases
h: length of the height
Volume of a cube: V=a3
a: length of one side
Volume of a box: v=l × w × h
l: length
w: width
h: height
Volume of a sphere: v=(4/3) × π × r3
π: 3.14
r: radius of sphere
Volume of a cylinder: V=πr2h
π: 3.14
r: radius of the circle of the base
h: height of the cylinder
അക്ബറിന്റെ നിർമ്മിതികൾ .
കോഡ് - ALFI യ്ക്ക് BP യുണ്ട്.
A - ആഗ്രാ കോട്ട, അഹമ്മദാബാദ് കോട്ട.
L - ലാഹോർ കോട്ട.
F - ഫത്തേപ്പൂർ സിക്രി (ചെങ്കല്ലിലെ ഇതിഹാസം).
I - ഇബാദത്ത് ഘാന (ഫത്തേപൂർ സിക്രിയിലെ ആരാധനാലയം).
B - ബുലന്ദ് ദർവാസ (ഫത്തേപൂർ സിക്രിയുടെ പ്രവേശന കവാടം).
P - പഞ്ച് മഹൽ.
അക്ബറുടെ ശവകുടീരം സ്ഥിതിചെയ്യുന്നത് - സിക്കിന്ദ്ര (ആഗ്ര) .
അക്ബർ ന...
Problems Type 1: .
A can finish work in X days. .
B can finish work in Y days.
Both can finish in Z days = (X*Y) / (X+Y). .
Problems Type 2: .
Both A and B together can do work in T days.
A can do this work in X days.
then, B can do it in Y days = (X*T) / (X-T) .
Problems Type 3: .
A can finish work in X days.
B can finish work in Y days.
C can finish work in Z days.
Together they can do work in T days = (X*Y*Z)/ [(X*Y)+(Y*Z)+(X*Z)] .
Problems Type 4: .
A can finish work in X days.
B can finish work in Y days.
A*X = B*Y.
...
What is the divisibility by 2 Rule?.
Even numbers are multiples of 2. A number is even if ends in 0,2,4,6, or 8.
What is the divisibility by 3 rule?.
A number is divisible by 3 if the sum of its digits is divisible by 3.
372, for instance, is divisible by 3 since sum of its digits (3+7+2) is 12. And 12 is divisible by 3.
What is the divisibility by 4 rule?.
A number is divisible by 4 if the number\'s last two digits are divisible by 4.
9,312, for instance, is divisible by 4 since its last 2 digits are 12. And 12 is divisible by 4.
What is the divisibility by 5 rule?.
A number is divisible by 5 if its last digit is a 0 or 5.
What is the divisibility by 6 rule?.
Since 6 is a multiple of 2 and 3, the rules for divisibility by 6 are a combination of the rule for 2 and the rule for 3.
Divisibility by 8 Rule.
A number passes the test for 8 if the las...